Find the x-intercept(s) and the coordinates of the vertex for the parabola =y−x2−2x3. If there is more than one x-intercept, separate them with commas.

Step-by-step explanation:

Your equation makes no sense.

I will ASSUME you mean

y = -x² - 2x + 3

which can be factored

y = (x + 3)(-x + 1)

x intercepts occur when y = 0

0 = (x + 3)(-x + 1)

which means either

x + 3 = 0

x = -3

or

-x + 1 = 0

x = 1

x intercepts are (-3, 0) and (1, 0)

The vertex will occur halfway between these point

x = (-3 + 1) / 2 = -1

so vertex = y = -(-1)² - 2(-1) + 3 = 4

(-1, 4)

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

triangle and cube

step-by-step explanation: