Which equation could possibly represent the graphed function? OA. f(x) = (x-4)(x + 2)(x + 4)
OB. f(x) = (x-4)^2(x - 2)
OC. f(x) = (x+4)^2(x+2)
OC. f(x) = (x-4)(x-2)(x+4)

A

Step-by-step explanation:

You're looking for x-intercepts

From the graph you know that the x-intercepts are as follows:

x = -4, x = -2, x = 4

And this is when y or f(x) = 0

so you can rewrite each x-intercept as an equation

0 = x + 4

0 = x + 2

0 = x - 4

Now you know each of the terms

f(x) = (x-4)(x+2)(x+4)

A choice.

Step-by-step explanation:

If you notice, you see the graph having x-intercepts which are x = 4, -2 and -4.

Because the graph passes through x = 4, -2 and -4, we have to find the function that satisfy x-values when f(x) = 0.

Finding x-intercepts, let f(x) = 0.

A choice

f(x) = (x-4)(x+2)(x+4)

Let f(x) = 0 to find x-intercepts.

0 = (x-4)(x+2)(x+4)

Then solve the equation like linear.

Hence, x = 4,-2,-4

Since the x-intercepts are (4,0),(-4,0) and (-2,0), it satisfies the graph and therefore A is correct.

it's

move it to the other side

step-by-step explanation: