Please help algebra. quadratic formulas
Please specify question number in your answer.

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Step-by-step explanation:

Area of a trapezoid =

height * ( sum of base lengths) / 2

So...let the height = h

One base = h + 3

And the other is h + 5

So...we have this

375 = h [ (h + 3 + h + 5 ] / 2 multiply both sides by 2

750 = h [ 2h + 8 ]

750 = 2h^2 + 8h rearrange as

2h^2 + 8h - 750 = 0

Using the quadratic formula....we get the answer ≈ 17.468 = 17.5 yards (rounded)

"b" is correct

For the quadratic equation

ax2+bx+c=0

the formula for the roots is

x=−b±√b2−4

ac2a(1)

Identify the values for

a,b,&cx2+4x+3=0

cmp

ax2+bx+c=0a=1b=4c=3(2)

Substitute these numbers into eh formula

x=−4±√42−(4×1×3)2×1(3)

Carefully proceed and do the calculations

x=−4±√16−122x=−4±√42x=−4±22

now calculate the two separate solutions

x1=−4+22=−22=−1x2=−4−22=−62=−3

c

step-by-step explanation: