Someone help plz plzz

tanC = 6/21  = tan-1

tan theta = opp/adj = 6/21 = tan-1 all are inverse tangents.

= 15.9453959 degree

We also need to keep in mind that hypotenuse that isnt whole number can be simplified like this.

Cos = adj/hyp = 21 / Sqrt 477 x sqrt477 / sqrt 477 = 21sqrt477/ 477

arctangent(opp/adj) = q: ... tan-1  arccsc-1, arcsec-1, and arccot-1.

Just remember tan-1 if no angles given.

Step-by-step explanation:

6^2 + 21^2 = c^2

c^2 = srt 477 = 21.8403297

c angle =  tan-1 (6/21) = 15.945°

∠α = arcsin(a)

c

=  arcsin (6)  21.8403297

=arcsin(0.27472112749287)

=0.2783 rad = 15.945° = 15°56'43"

Therefore tan-1 6/21  = arcsin (6) x 21.640397 = 15.945°  

it has 4

step-by-step explanation:

les

elee

fg

elle

fetish

ser

el

le

f

lent

clee hd

lg

ad

be

hu

te

see

te

ele

cele

her

t

errel

c

s​

answer: 7270

step-by-step explanation: