The sum of 3 consecutive even integers is 36. What is the first of the 3 integers? HURRY I NeED HELP I’ll give brainliest

Given that the sum of 3 consecutive even integers is 36, we can define the variables to be:

And we can set up the equation as:

The first even number which we assumed was N, which is equal to 10.

And hence the answer will be

Verification:

3 consecutive even no.s :

Their sum = 10 + 12 + 14 = 36

Hence, N = 10 is the solution of the question.

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: