Each graph shows two polygons ABCD and A'B'C'D'. In each case, describe a sequence of transformations that takes `ABCD` to `A'B'C'D'.`

we know that

1) the inscribed angle measures half of the arc it comprises.

so

m∠dgf= > expression

2) the opposite angles in an inscribed quadrilateral are supplementary angles

so

m∠dgf=

m∠dgf=°

substitute in the expression to find the value of arc ef

therefore

the answer is

the measure of the arc ef is

666

step-by-step explanation:

to find perimiter, add all the sides.

60 5/6 + 54 1/3 + 59 1/3 + 56 1/6.

goup like terms:

(60 5/6 + 56 1/6) + ( 54 1/3 + 59 1/3) = 117 + 113 2/3

56 + 60 =   116. 5/6 + 1/6 = 6/6 = 1/ 116 + 1 = 117

54 + 59 = 13. 1/3 + 1/3 =2/3. 13 + /3 = 113 2/3    

117 + 113 2/3 = 230 2/3

answer: 230 2/3