Write the equation of a line that is perpendicular to y = 3x - 2 and goes through the point (0,5)

y = -1/3x + 5

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes. This means that if you multiply the slopes of both linear equations, the product will be -1.

Given the linear equation, y = 3x - 2, and the point (0, 5):

The negative reciprocal of the slope (m) = 3 is -1/3. Hence, we can assume that the slope of the other line must be -1/3.

Next, using the slope of the other line (m = -1/3) and the given point, (0, 5), we'll substitute these values into the slope-intercept form, y = mx + b, to solve for the y-intercept (b):

y = mx + b

5 = -1/3(0) + b

5 = 0 + b

5 = b

The y-intercept (b) of the other line is 5.

Therefore, the linear equation of the line perpendicular to y = 3x - 2 is:

y = -1/3x + 5

Please mark my answers as the Brainliest if you find my explanations helpful :)

my guess would be b and d, but i didn’t actually get out the pen and paper. lol