Town's population has been growing linearly. in 2003, the population was 2, and the population has been growing by 1700 people each year.

write an equation for the population x years after 2003

An equation for the population x years after 2003 is

Step-by-step explanation:

Since we have given that

Population in 2003 = 20000

Number of population growing each year = 1700

Let the number of years after 2003 be 'x'.

So, our equation becomes,

Hence, an equation for the population x years after 2003 is

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²