Cameron has 30 coins in his pocket, all of which are dimes and quarters. If the total value of his change is 450 cents, how many dimes and how many quarters does he have?

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Step-by-step explanation:

If all of the coins were dimes, the 30 coins would have a value of 300 cents. Their actual value is 450 -300 = 150 cents more than that.

Replacing a dime with a quarter adds 25 -10 = 15 cents to the value. Since the value is 150 cents greater than for all dimes, there must be 150/15 = 10 quarters in the mix.

There are 10 quarters and 20 dimes in Cameron's pocket.

Cameron has 30 coins in his pocket, all of which are dimes and quarters. If the total value of his change is

450 cents, how many dimes and how many quarters does he have?

There are 10 quarters and 20 dimes in Cameron's pocket.

Step-by-step explanation:

Since the value is 150 cents greater than for all dimes, there must be 150/15 = 10 quarters in the mix.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.