What solution is y = 2x + 2 y = -2x + 4 ?

x = , y = 3

Step-by-step explanation:

y = 2x + 2 → (1)

y = - 2x + 4 → (2)

Substitute y = 2x + 2 into (2)

2x + 2 = - 2x + 4 ( add 2x to both sides )

4x + 2 = 4 ( subtract 2 from both sides )

4x = 2 ( divide both sides by 4 )

x = =

Substitute this value into (1) for value of y

y = 2( ) + 2 = 1 + 2 = 3

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.