An 18.0 g piece of an unidentified metal was heated from 21.5 °C to 89.0 °C. If 789.75 J of heat energy was absorbed by the metal in the heating process, what was the identity of the metal?

The metal is Calcium.

Explanation:

To calculate the specific heat of substance during the reaction.

where,

q = heat absorbed = 789.75 J

c = specific heat of metal = ?

m = mass of substance = 18.0 g

= final temperature  - initial temperature  =

Now put all the given values in the above formula, we get:

As specific heat is characteristic of each metal and thus the metal is calcium which has  specific heat of

distance, luminosity, brightness, radius, chemical composition, and temperature

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.