A bookstore sells textbooks for $120 each and notebooks for $6 each. The bookstore would like to sell $1,080 in merchandise by the end of the week. Graph the linear equation 120t + 6n = 1080, where t is the number of textbooks sold, and n is the number of notebooks sold.

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )

w< 4

step-by-step explanation: