The formation of h2 from two h atoms is an energetically favorable process. yet statistically there is less than a 100 percent chance that any two h atoms will undergo the reaction. apart from energy considerations, how would you account for this observation based on the electron spins in the two h atoms ?

What is the typical rotational frequency frot for a molecule like n2 at room temperature (25∘c)? assume that d for this molecule is 1å=10−10m. take the total mass of an n2 molecule to be mn2=4.65×10−26kg. you will need to account for rotations around two axes (not just one) to find the correct frequency. express frot numerically in hertz, to three significant figures.