Find two consecutive even numbers whose sum is 126

62+64 = 126

Step-by-step explanation:

If 126/2=63, then 62+64 = 126

62 + 64 = 126

Step-by-step explanation:

x + (x+2) = 126

x + x = 126 - 2

x + x = 124

2x = 124

x = 124 : 2

x = 62

x + (x-2) = 126

x + x = 126 + 2

x +x = 128

2x = 128

x = 128 : 2

x= 64

Los números son 62 y 64.

Ya que:

62 + 64 = 126

Son pares consecutivos ya que los dos números son pares (los números pares terminan en 0,2,5,6 o 8 ) y son consecutivos ya que uno le sigue al otro. (El 63 no se cuenta ya que es impar.)

6/20

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a