So the problem is number 8 and number 9 8.If mABC is one degree less than three times mABD and mDBC = 47°,find each measure.
9.If QS bisects PQT, mSQT = (8x – 25)°, mPQT = (9x + 34)°, and mSQR = 112°
, find each measure.

sgth thdhtxr ythdsx hfgh ysrth th srtrh

step-by-step explanation:

trshd h rdhsjsdrnytjdt jyjyukfddythj

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

246

step-by-step explanation:

it would be 3 ÷by 6 because the number on each side