Solve the following system of equations. 4y+3z=-7
12x-3y+z=-7
-6x+2y-2z=12

Step-by-step explanation:

12x-3y+z＝-7 ‖-12x+3y

z＝-7-12x+3y

so you can replace z with (-7-12x+3y)

4y+3*(-7-12x+3y)＝-7

4y+(-21-36x+9y)＝-7

13y-21-36x＝-7 ‖+21

13y-36x＝14 ‖-13y

-36x＝14-13y ‖*(-1)

36x＝-14+13y ‖/3

12x＝-14/3+13/3y

so-6x＝+14/6-13/6y

(+14/6-13/6y)+2y-2*(-7-(-14/3+13/3y)+3y)＝12

(+14/6-13/6y)+2y+14-28/3+26/3y-6y＝12

(+14/6-13/6y)+2y+14-56/6+52/6y-6y＝12

7+2.5y＝12 ‖-7

2.5y＝5 ‖/2.5

y＝2

so

4y+3z＝-7

4*2+3z＝-7

8+3z＝-7 ‖-8

3z＝-15 ‖/3

z＝-5

12x-3*2+(-5)＝-7

12x-6-5＝-7

12x-11＝-7 ‖+11

12x＝4 ‖/12

x＝1/3

the answer is a

step-by-step explanation:

maybe i can