the perimeter of a rectangle is 68 feet the length is 5 inches shorter than twice the width what are the dimensions of the rectangle

Step-by-step explanation:

The perimeter formula is P = 2L + 2W. If the perimeter is given as 68 feet, then our P will be filled in with 68. If the length is "5 inches shorter than twice the width" is an expression that looks like this, keeping in mind that "shorter" means subtraction, "twice" means doubled, and the word "is" means equals:

L = "length is"

2W is "twice the width"

5 inches shorter is " - 5". Putting it all together:

L = 2W - 5. Now we can fill in the perimeter formula:

68 = 2W + 2(2W - 5) and

68 = 2W + 4W - 10 and

68 = 6W - 10 and

78 = 6W so

W = 13. The width is 13 inches and the length is

L = 2(13) - 5 so the length is

L = 21 inches.

any options?

step-by-step explanation:

b is the correct answer