Solve the following systems of equations using the substitution method. 6x + 2y = 82 and x − y = 3 y = 4x − 1 and x + y = 9 4x + 3y =17 and y = 5 − x

Step-by-step explanation:

puhhh ! that way of typing can be misleading.

let me sum up what equations I think the problem definition specified :

1)

6x + 2y = 82

x - y = 3

2)

y = 4x - 1

x + y = 9

3)

4x + 3y = 17

y = 5 - x

solving 1)

x - y = 3 => x = y + 3

putting this into the first equation

6×(y+3) + 2y = 82

6y + 18 + 2y = 82

8y +18 = 82

8y = 64

y = 8

x = y + 3 = 8 + 3 = 11

solving 2)

using the first equation in the second equation

x + (4x - 1) = 9

5x - 1 = 9

5x = 10

x = 2

y = 4x - 1 = 4×2 - 1 = 8 - 1 = 7

solving 3)

using the second equation in the first equation

4x + 3×(5 - x) = 17

4x + 15 - 3x = 17

x + 15 = 17

x = 2

y = 5 - x = 5 - 2 = 3