FOLLOW THE STEPS TO MAKE THE CONSTRUCTION. WILL MARK BRAINLIEST!! THIS IS ONE QUESTION JUST FOLLOW THE STEPS. Step 1:
Using a straightedge, draw a line segment. Draw endpoints and label them P and Q.

Step 2:
Draw a new point that is not on PQ¯¯¯¯¯¯¯¯ and label the point N.

Step 3:
Use a compass to match the distance of PQ¯¯¯¯¯¯¯¯. Do not change the compass setting.

Step 4:
Keep the compass setting from Step 3 and place the needle of your compass on point N and draw an arc (part of a circle).

Step 5:
Draw a point on the arc and label the point M.

Step 6:
Using a straightedge, draw a segment that connects N to M.

Step 7:
Using a ruler, measure PQ¯¯¯¯¯¯¯¯ and MN¯¯¯¯¯¯¯¯¯¯. Write those measures on your construction.

Verify that the distance of each segment has the same measure: PQ=MN.

Given: ad¯¯¯¯¯ is an altitude. prove: ab2+ac2=cb2 right triangle a b c with right angle a. point d lies on side b c and segment a d is drawn. angle a d c is a right angle. drag and drop a reason into each box to correctly complete the two-column proof. statement reason ad¯¯¯¯¯ is an altitude, and ∠bac is a right angle. given ∠adb and ∠adc are right angles. definition of altitude ∠bac≅∠bda ? ∠bac≅∠adc ? ∠b≅∠b ? ∠c≅∠c reflexive property of congruence △abc∼△dba ? △abc∼△dac aa similarity postulate abbd=cbab ? ab2=(cb)(bd) cross multiply and simplify. acdc=cbac polygon similarity postulate ac2=(cb)(dc) cross multiply and simplify. ab2+ac2=ab2+(cb)(dc) addition property of equality ab2+ac2=(cb)(bd)+(cb)(dc) substitution property of equality ab2+ac2=(cb)(bd+dc) ? bd+dc=cb segment addition postulate ab2+ac2=cb2 substitution property of equality