A professor wants to make sure that two different versions of a test are equivalent. He decides to compare the variances of the test scores from each version. A sample of 24 scores on Version A has a sample variance of 1.161, while a sample of 17 scores from Version B has a sample variance of 3.627. Required:
Construct a 90 % confidence interval for the ratio of the population variances of the scores on the two versions of the test. Round the endpoints of the Interval to four decimal places, if necessary.

d 192

step-by-step explanation:

we find our area to find area we multiply thoses numbers to get our answer so our area is 192

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

idek

step-by-step explanation:

pls refer ro the top for answer