Calculate the ph of the solution formed when 45.0 ml of 0.100m naoh solution is added to 50.0 ml of 0.100m ch3cooh (ka for acetic acid = 1.8 x10-5 ).

pH of soltion will be 5.69

Explanation:

The pH of the solution will be due to excessive acid left and the salt formed. Thus, it will form a buffer solution.

The pH of buffer solution is calculated from Henderson Hassalbalch's equation, which is:

The moles of acid taken :

The moles of base taken:

The moles of acid left after reaction :

The moles of salt formed = 4.5mmol

Putting values in equation

i dont know

explanation:

"the periodic table is arranged in order of atomic number."