If two natural numbers are n and (n+3) prove that the differences of their square is an even numbers

Answer and explanation:

Given two natural numbers n and n+3, we prove that the difference or their squares is even thus:

(n+3)²-(n)²= (n+3)(n+3)-(n)²

=n²+3n+3n+9-n²

=6n+9

Since the value of the difference of square of the natural numbers n and n+3 is in the form 6n+9, the difference is not an even number.