7. a rectangular play area is to be bounded by 120 m of fencing.
determine the maximum area and the dimensions of this rectangle.

31×29m

Step-by-step explanation:

120÷4=30

Each side would be 30 but since it must be a rectangle make 2 sides 29 and the other 2 31. making it the maximum dimensions possible.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet