If a parachutist lands at a random point on a line between markers A and B, find the probability that she is closer to A than to B. Find the probability that her distance to A is more than seven times her distance to B.

Answer and Step-by-step explanation:

The random point on the line is between A and B, and to find the probability of the A, let's find the probability that is distance A and more than times the distance B. Let's have the probability that A and distance to A are more than the distance to B. The distance C is the interval of A to B. If she is closer and landed in the interval, the equation can be (A, A+B/2). This is the interval length, and the probability is 0.5. If the distance to A is more than the distance B, then the interval is as follows in the given equation (A + 3B/2, B ). The probability of the given interval is 0.25.

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

c

-by-step explanation:

it would be c