The amount of snowfall falling in a certain mountain range is normally distributed with a average of 170 inches, and a standard deviation of 20 inches. What is the probability a randomly selected year will have an average snofall above 200 inches

0.0668 = 6.68% probability a randomly selected year will have an average snowfall above 200 inches.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a average of 170 inches, and a standard deviation of 20 inches.

This means that

What is the probability a randomly selected year will have an average snowfall above 200 inches?

This is 1 subtracted by the p-value of Z when X = 200. So

has a p-value of 0.9332.

1 - 0.9332 = 0.0668

0.0668 = 6.68% probability a randomly selected year will have an average snowfall above 200 inches.

over the argument its not good to fight.

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.