At a snack food manufacturing facility, the quality control engineer must ensure that all products feature the appropriate expiration date. Suppose that a box of 60 candy bars includes 12 which do not have the proper printed expiration date. The quality control engineer, in inspecting the box, grabs a handful of seven candy bars. What is the probability that there are exactly 3 faulty candy bars among the seven

0.1108 = 11.08% probability that there are exactly 3 faulty candy bars among the seven.

Step-by-step explanation:

The bars are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

is the number of different combinations of x objects from a set of n elements, given by the following formula.

In this question:

60 total candies means that

12 are faulty, which means that

Seven are chosen, so

What is the probability that there are exactly 3 faulty candy bars among the seven?

This is . So

0.1108 = 11.08% probability that there are exactly 3 faulty candy bars among the seven.

you cant answer this dummy

step-by-step explanation:

his chances of getting a coin of higher value is 4/19

step-by-step explanation: