1ª QUESTÃO) (IFS – 2013) A parábola representada pela função abaixo, corta o eixo das abscissas nos pontos: (A) (0, 0) e (3, 0)
(B) (0, 1) e (0, 2)
(C) (1/2, 0) e (1/3, 0)
(D) (0, 6) e (0, – 5)
(E) (1/6, 0) e (−1/5, 0)

Consider the linear model for a two-stage nested design with b nested in a as given below. yijk=\small \mu + \small \taui + \small \betaj(i) + \small \varepsilon(ij)k , for i=1,; j= ; k=1, assumption: \small \varepsilon(ij)k ~ iid n (0, \small \sigma2) ; \small \taui ~ iid n(0, \small \sigmat2 ); \tiny \sum_{j=1}^{b} \small \betaj(i) =0; \small \varepsilon(ij)k and \small \taui are independent. using only the given information, derive the least square estimator of \small \betaj(i) using the appropriate constraints (sum to zero constraints) and derive e(msb(a) ).