use algebraic manipulation to find the minimum sum-of-products expression for the function x1x2'x3' + x1x2x4+x1x2'x3x4'

sum of products expression = x₁x₂x₃'  +  x₁x₂'x₄  + x₁x₂x₄

Step-by-step explanation:

Given function ( f ) = x₁x₂'x₃'  +  x₁x₂x₄ + x₁x₂'x₃x₄'

using algebraic manipulation

f = x₁ [ x₂'x₃'  +  x₂x₄ + x₂'x₃x₄' ]

 =  x₁ [ x₂'( x₃' + x₃x₄') +  x₂x₄  ]

next apply Boolean rules

a + bc = ( a + b )(a + c )

a' + a =1

hence

minimum sum-of-products expression = x₁x₂x₃'  +  x₁x₂'x₄  + x₁x₂x₄

what do u need to know

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages