a ladder 6m long leans against the wall of house if the foot of the ladder makes an angle 58 degree with tye ground how far is the base of ladder from the wall​

Length of ladder =6 m

Ladder reaches the wall to a height of 4.8 m

Consider AB as the ladder and AC as the height of the wall

AB=6 m and AC=4.8 m

Distance between the foot of ladder and wall is BC

Using Pythagoras theorem,

AB

2

=AC

2

+BC

2

Substituting the values

6

2

=4.8

2

+BC

2

By further calculation

BC

2

=6

2

−4.8

2

BC

2

=36−23.04=12.96

So we get

BC=√12.96=3.6 m

Step-by-step explanation:

hope it's helpful