Which equation in point-slope form contains the point (4, –1) and has slope 3? y + 1 = 3(x – 4)

y – 4 = 3(x + 1)

y – 1 = 3(x + 4)

y + 4 = 3(x – 1)

y+1=3(x-4)

Step-by-step explanation:

Hi there!

We are given a slope of 3 and a point (4,-1).

We need to find the equation of the line in point-slope form

Point-slope form is given as y-y1=m(x-x1), where m is the slope, and (x1,y1) is a point

We have all of the needed information to substitute into the formula

First, let's label the values of everything to avoid any confusion

m=3

x1=4

y1=-1

now substitute into the formula *remember, the formula has SUBTRACTION, and we have a NEGATIVE number, so we'll end up subtracting a negative*

y--1=3(x-4)

simplify

y+1=3(x-4)

That's it!

Hope this helps :)

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step-by-step explanation:

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