Mathematics, 17.06.2021 05:10 lorihab1970

Verify which of the following are identities. 1) 8 sec theta sin theta = 8 cot theta tan ^2 theta
2) 11 cot^2 theta/csc theta sec^2 theta = qq tan theta cos theta csc^2 theta
a.
Only the first equation is an identity.
b.
None of the equations are identities.
c.
Only the second equation is an identity.
d.
Both the equations are identities.

Answers: 1

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Answer from: Quest

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

$f(x) =\sqrt{x}$

this can also be written as

$y^{2} =x$

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

Answer from: Quest

i believe the answer is 323 ft

step-by-step explanation:

Alarge asteroid crashed into a moon of another planet causing several boulders from the moon to be p

Answer from: Quest

Answer: f(x) = -2x^3 +3x^2 +11x -6see attachedan infinite number. since the magnitude of the leading coefficient is not specified, it may be any negative number. (we have chosen the smallest magnitude integer that makes all coefficients be integers.)step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

Answer from: Quest

Hello!

the answer is:

the lateral area is equal to $352m^{2}$

$lateralsidearea=352m^{2}$

why?

to find the lateral area of the square pyramid, first we need to find the perimeter of the base, and then, find the lateral area using the following formulas:

$baseperimeter=4s$

$lateralsidearea=\frac{1}{2}baseperimeter*slantheight$

where,

s, is the base length

slant height, is the height of a the side of the pyramid

we are given:

$s=8m\\slantheight=22m$

now, calculating the perimeter of the base, we have:

$baseperimeter=4s=4*8m=32m$

then, calculating the lateral area:

$lateralsidearea=\frac{1}{2}baseperimeter*slantheight$

$lateralsidearea=\frac{1}{2}32*22m=352m^{2}$

hence, we have that the lateral area is equal to $352m^{2}$

have a nice day!

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Verify which of the following are identities. 1) 8 sec theta sin theta = 8 cot theta tan ^2 theta

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