a. segment AB congruent
segment CD
b. segment AB congruent d. segment BC
c. segment AD congruent segment BC
d. segment AC congruent segment BD

A. Segment AB congruent segment CD

C. Segment AD congruent segment BC

Step-by-step explanation:

These are both true because a characteristic of a rhombus is that all four sides are congruent. Therefore we must prove that AB is congruent to CD and AD is congruent to BC.

answer: the answer to your question is parallel

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.