You measure 37 dogs' weights, and find they have a mean weight of 69 ounces. Assume the population standard deviation is 9.2 ounces. Based on this, construct a 90% confidence interval for the true population mean dog weight. Give your answers as decimals, to two places ± ounces (Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172 ; Enter DNE for Does Not Exist, oo for Infinity)

Solution :

Given :

mean weight of the dogs, = 69

Number of dogs, n = 37

Standard deviation, σ = 9.2

Confidence interval = 90%

At 90% confidence interval for the true population mean dog weight is given by :

= (66.5122, 71.4878)

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

i will pick c put check it over to be sure

step-by-step explanation: