What is the area and perimeter of the triangle

Area = 20yd

Perimeter = 23 yd

Step-by-step explanation:

Area = 1/2 ×bh

b, which I the base = 10yd

h, which is the height = 4yd

Note: 5yd is the base because when you turn the triangle you will see that 10yd is the base and 5yd is the height not 8yd because 8 yd is not a straight line at a right angle

Therefore;

Area = 1/2× 10 × 4

= 1× 5 × 4

= 20yd

Perimeter = 8yd +5yd +10yd

= 13yd + 10yd

= 23yd

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length