Hi, i know this is basic math and stuff but I still need some help​

Answers:

==============================================

Explanation:

The perimeter is the total distance around the outer edge of the figure. It's the total amount of fence you need to enclose the region.

So we simply add up all the side lengths. Refer to the diagram to see any missing sides that aren't labeled (shown in blue).

For instance, the perimeter for problem 1 is 5+2+2.5+4+2.5+6 = 22 cm. Problems 2 and 3 are handled the same way.

It's not a typo that the perimeters of problems 1 and 2 are the same value. This is because both figures can be surrounded by a rectangle that is 6 cm across and 5 cm tall. The perimeter of the surrounding rectangle is exactly the same as the perimeter of the inner fenced region. We're effectively just moving fence around but not changing the perimeter.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)