A construction crew is using heavy equipment to dig a hole in which the foundation of a house will be built. The hole will be in the shape of a right rectangular prism with dimensions of 4 feet in depth, 100 feet long, and 50 feet wide.
The soil will be removed using a truck that can hold a maximum of 40,000 pounds. The soil weighs 90 pounds per
cubic foot. What is the least number of truckloads needed to remove all of the soil?

5

Step-by-step explanation: volume of hole = 100x50x4=20,000 ft

soil weighs : 20000x90=180,000 pounds

180,000 divided by 40,000 = 4.5 ≈ 5

So the least number of truckloads is 5

yor answer is 7/6 times 5

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2