A fair die is rolled 12 times. Consider the following three possible outcomes: (i) 2 2 2 2 2 2 2 2 2 2 2 2
(ii) 1 1 2 2 3 3 4 4 5 5 6 6
(iii) 4 6 2 1 3 5 2 6 4 3 1 5
Which of the following is true?

It is absolutely impossible to get sequence (i).

(ii) is more likely than (i).

(iii) is more likely than (i) or (ii).

The three outcomes are equally likely.

Both (B) and (C) are true.

i can you answer this question sweetie!

step-by-step explanation:

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~