The lateral area of a cylinder is 100pi in^2. If its dimensions are reduced to one-fifth their original length, what would its new area be?

4pi in^2

Step-by-step explanation:

Lateral surface area of a cylinder = 2πrh

π = pi

r = radius

h = height

Let me illustrate with an example

A cylinder has the following dimensions

r = radius = 20  

h = height  = 10

lateral area = 2 x π x 20 x 10 = 400π

If dimensions are reduced to one-fifth their original length, new dimensions are

r = radius = 20  x 1/5 = 4

h = height  = 10 x 1/5 = 2

New lateral area = 2 x 4 x 2 x π = 16π

change in lateral area = 400π / 16π = 25

If dimensions are reduced by 1/5, lateral area would reduce by 25

100 pi / 25 = 4

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !

b

step-by-step explanation:

multiply terms on numerator/ denominator by (x - 1)

= ← distribute numerator/ denominator

= ← simplify

=

= → b