The five-number summary of a data set is given below. Minimum: 3 Q1: 12 Median: 15 Q3: 16 Maximum: 20

Which of the following is a true statement about outliers for this distribution?

The distribution’s maximum is an outlier.
The distribution’s minimum is an outlier.
There are no outliers for this distribution.
Distribution outliers cannot be determined.

The distribution's minimum is an outlier.

Step-by-step explanation:

Interquartile range is Q3 - Q1 = 16 - 12 = 4

1.5 * IQR = 1.5*4 = 6

Q1 - 6 = 12 - 6 = 6

Q3 + 6 = 16+6 = 22.

Now 3 is outside the range 6-22 but 20 isn't so 3 is an outlier.

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1

change of stock price/initial stock price on friday * total stock value = change of stock value

0.89/73.73 *x = 42.72

x=3539.04 = total stock value at initial stock price on friday .

total stock value at initial stock price on friday/ initial stock price on friday = number of shares

3539.04/73.73 = 48 shares

they own 48 shares of this stock