Physics, 11.02.2020 06:19 starreee

You will need to use the Momentum Principle to do the first part of this problem, and the Energy Principle to do the second part. A satellite of mass 4500 kg orbits the Earth in a circular orbit of radius of 9.3 106 m (this is above the Earth's atmosphere).The mass of the Earth is 6.0 1024 kg.
1. What is the speed of the satellite? (m/s)
2. What is the minimum amount of energy required to move the satellite from this orbit to a location very far away from the Earth?

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Answer from: Natasha019

Answer

given,

Mass of satellite, m = 4500 kg

Mass of the earth, M = 6 x 10²⁴ Kg

Earth circular orbit radius, R = 9.3 x 10⁶ m

a) To find the speed of the satellite

we need to equate the gravitation force between earth and satellite with the centripetal force.

$\dfrac{GMm}{R^2}=\dfrac{mV^2}{R}$

$V = \sqrt{\dfrac{GM}{R}}$

$V = \sqrt{\dfrac{6.67\times 10^{-11}\times 6\times 10^{24}}{9.3\times 10^6}}$

V = 6559.89 m/s

b) Minimum amount of energy of satellite

$E = \dfrac{GMm}{r}-\dfrac{1}{2}mv^2$

$E =\dfrac{6.67\times 10^{-11}\times 6\times 10^{24}\times 4500}{9.3\times 10^6}}-\dfrac{1}{2}\times 4500\times 6559.89^2$

E = 9.68 x 10¹⁰ J

Minimum amount of energy require to move satellite is equal to E = 9.68 x 10¹⁰ J

Answer from: ambriaramirez8

The minimum amount of energy that is required to move the satellite is 9.68 x 10¹⁰ J.

A) The speed of the satellite can be calculated by equating the gravitational force and centripetal force on the satellite,

$\begin {aligned} \dfrac {GMm}{R^2} &= \dfrac {m V^2}R\\\dfrac {GM }R&= V^2\\V& = \sqrt {\dfrac {GM}R}\end {aligned}$

Where,

= speed of satellite =?

- gravitational constant = $6.67 \times 10^{-11}$

- mass of earth = 6 x 10²⁴ Kg

- radius of the circular orbit of satellite = 9.3 x 10⁶ m

Put the value in the formula, we get:

V = 6559.89 m/s

B) Minimum amount of energy of satellite to move

$E =\dfrac {GMm}{R} - \dfrac 12 mv^2$

Put the values in the formula, we get:

E = 9.68 x 10¹⁰ J

Therefore, the minimum amount of energy that is required to move the satellite is 9.68 x 10¹⁰ J.

To know more about gravitational constant,

Answer from: Quest

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.

Answer from: Quest

lol

explanation:

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