What transformations were applied to ABCD to obtain A'B'C'D? B
С
8
6
C'
DI
A
4
2
A
B
-12
-10
-5
4
4
2
-4
8
A. Rotate 90 degrees counterclockwise about the origin, then
translate 2 units left

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

my computer is slow i can not see it sorry

11) obtuse

13)right

15) acute