The length of one leg of a right triangle is 20.3 centimeters. The length of the hypotenuse is 30.7 centimeters. Which is closest to the length of the other leg?

Work Shown:

a = 20.3

b = unknown

c = 30.7

Apply the pythagorean theorem to find b

a^2 + b^2 = c^2

(20.3)^2 + b^2 = (30.7)^2

412.09 + b^2 = 942.49

b^2 = 942.49-412.09

b^2 = 530.4

b = sqrt(530.4)

b = 23.0304146727757  value is approximate

b = 23.0

I rounded to one decimal place because the other values (20.3 and 30.7) were to one decimal place.

ok

step-by-step explanation: