Is algebra. PLEASE HELP NO LINKS OR FILES.
I don't want links.
I don't want links.
I don't want links.
I don't want links.

1) b   2) b

Step-by-step explanation:

1) Both expressions have (x+6). Rearrange them and you'll have one expression as (x+6) and the other as (5ab-4).

2) (4b - 7x)(a + b) factors to be 4ba + 8b - 7ax - 14x, which can be rearranged to 4ab - 7ax + 8b - 14x

Question 1

Explanation:

Note how we have (x+6) show up twice. What we can do is erase both copies to end up with 5ab-4. Then stick parenthesis around that to get (5ab-4). Effectively what is going on here is that we're pulling out the GCF (x+6).

Lastly, tack on the (x+6) we erased earlier to get the factorization of (5ab-4)(x+6). Because multiplication can be done in any order, this means it's the same as (x + 6)(5ab - 4)

We can use the distribution method, the box method, or FOIL to expand that factorization back out and help confirm we have the correct answer.

Question 2

Explanation:

We'll use the factor by grouping method.

Pair up the terms, then factor each grouping pair. From there, you'll follow the ideas mentioned in problem 1 to finish things off.

This is what the steps could look like:

4ab - 7ax + 8b - 14x

(4ab - 7ax) + (8b - 14x) ... pair up terms

a(4b - 7x) + 2(4b - 7x) ... factor out GCF from each group

(a + 2)(4b - 7x) ... use the trick done in problem 1

(4b - 7x)(a + 2) the order of multiplication doesn't matter

You can use the distribution method, FOIL method, or box method to help confirm the answer.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}