Calvin glues 12 craft sticks onto paper for an art project. as shown below. Each craft stick is 3/8 in. wide, and calvin leaves a 1/12 in. space between craft sticks. Calvin says that the total width of the 12 craft sticks will be between 4.45 and 5.45 in. is calvin correct??

The total width of 12 craft sticks is _ ( twelve eighths, thirty- six eights) inches. the total width of the spaces between the 12 craft sticks is _( eleven twelves, twelves twelves) inches the total width of calvins art project is _ twenty four inches , which is between _ inches so calvin is _ (correct, incorrect)

answer: 1+1

step-by-step explanation: 1+1 is at least 2

the value of x is 9 ⇒ answer b

step-by-step explanation:

* we can solve this problem using cosine and sine rule

- in δ abc

∵ ab = 36 , bc = 28 , ac = 16

- lets find the measure of angle b using the cosine rule

∵ cos b = [ab² + bc² - ac²]/2(ab)(bc)

∴ cos b = [36² + 28² - 16²]/2(36)(28)

∴ cos b = 19/21

∴ m∠b = cos^-1(19/21) ≅ 25°

- lets find the measure of angle a using the sine rule

∵ sina/bc = sinb/ac = sinc/ab

∴ sina/28 = sin25°/16 ⇒ by using cross multiplication

∴ sina = 28 × sin25°/16

∴ sina = 0.7396

∴ m∠a = sin^-1(0.7396) ≅ 48°

- from the figure m∠abd = m∠dbc

∵ m∠abc = 25°

∴ m∠abd = 25°/2 = 12.5°

- in δabd

∵ m∠a = 48° , m∠abd = 12.5°

∵ the sum of the measures of the interior angles of any δ is 180°

∴ m∠adb = 180° - (48° + 12.5°) = 119.5°

∵ ab = 36

∵ ad = x

- use the sine rule to find x

∵ sin∠adb/ab = sin∠abd/x

∴ sin119.5°/36 = sin12.5°/x ⇒ by using cross multiplication

∴ x = 36 × sin12.5°/sin119.5° = 8.95 ≅ 9

* the value of x is 9

1/2(2*4)=6 $$- agahajakanajak

did u ever get the answers? i need