A metallurgist has one alloy containing 32% aluminum and another containing 44% aluminum. How many pounds of each alloy must he use to make 54 pounds of a third alloy containing 36% aluminum? (Round to two decimal places if necessary.)

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step-by-step explanation:

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !

if the rectangular pool has a area of 192 square ft. and length of 15 ft. you must divide 15 into 192. 192 ÷ 15 = about 13 ft.