At an ocean depth of 8 meters, a buoy bobs up and then down 5 meters from the ocean's depth. sixteen seconds pass from the time the buoy is at its highest point to when it is at its lowest point. assume at x = 0 the buoy is at normal ocean depth.

use the sine tool to graph the function. the first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

  See attached for a graph

Step-by-step explanation:

We're going to plot sea level as y=0 and a depth of 8 meters as y=-8.

The problem statement tells you the initial point (x=0) is at normal ocean depth (y=-8), so the first point you put into your sine tool is ...

  (x, y) = (0, -8)

The buoy takes 16 seconds to go from a high point to a low point, so the time to the first high point is half that, or x=8 seconds. That high point is 5 meters above its average depth, so is at y=-3.

The second point you will put into your sine tool is ...

  (x, y) = (8, -3)

step-by-step explanation:

their are no angles. sorry cant .

b). 4320 have a nice day