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Mathematics, 19.04.2021 23:38 thasen31

Adam solved this problem. His teacher said it was incorrect. Find his error and correct it. (a βˆ’ 3)(5a3 βˆ’ a2 + 2a βˆ’ 7) = (a)(5a3 βˆ’ a2 + 2a βˆ’ 7) βˆ’ (3)(5a3 βˆ’ a2 + 2a βˆ’ 7) = 5a4 βˆ’ a3 + 2a2 βˆ’ 7a βˆ’ 15a3 + 3a2 + 6a βˆ’ 21 = 5a4 βˆ’ 16a3 + 5a2 βˆ’ a βˆ’ 21

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Adam solved this problem. His teacher said it was incorrect. Find his error and correct it. (a βˆ’ 3)(...
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