Palo alto college is planning to construct a rectangular parking lot on land bordered on one side by a highway. the plan is to use 720 feet of fencing to fence off the other three sides. what dimensions should the lot have if the enclosed area is to be a maximum?

The length of the 3 sides has a total dimension of 720 ft. One dimension, the length l, only has one side enclosed. The other dimension, the width w, has 2 sides enclosed. So,

720 ft = l + 2w 

Rearranging in terms of l: 

l = 720 - 2w 

Then the area equals length times width, or: 

A = (720-2w)(w) = 720w - 2w^2 

To get the maximum area, we take the derivative of the Area equation and set the derivative equal to 0: dA/dw = 0 

dA/dw = 720 - 4w = 0 

720 - 4w = 0 
4w = 720

w = 180 ft

Calculating for l:

l = 720 – 2w

l = 720 – 2(180)

l = 360 ft

the square root of what number? if you add that, then someone will probably answer the question.

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.