Two iron weights, one twice the mass of the other, are dropped from the top of a building. compared with the lighter weight, the twice as heavy weight will hit the ground with?

If we neglet air resistance for both objects then both will fall parallely(at same time) because time taken by both objects is independent of mass. there is famous experiment i.e"feather coin experiment" . normally we think that heaver objects falls faster but this is wrong concept. it depends on medium in which objects are moving.
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Sorry i don’t know what to do

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j