What is the difference in kilowatt hours of monthly energy production between an average local wind speed of 15 miles per hour and a average local wind speed of 10 miles per hour

Renewable energy is the electricity that we can get from renewable sources such as hydropower, solar energy and wind power. For wind energy, factors of energy production are the average wind speed, air density, and the cross sectional area of the wind turbine. All these factors are accounted for in the equation for finding the theoretical power from wind:

P,theo = 1/2 ρAV³, where ρ is the air density which is approximately 1.225 kg/m³. A is the cross sectional area of the turbine and V is the wind speed.

However, the actual power that can be harnessed from wind power basing on industrial measurements, the efficiency is only 40%. So,

P,actual = 0.4(1/2 ρAV³) = 0.2ρAV³
Since A is not give, let's just keep it that way. Then,

P,actual₁ = 0.4(1/2 ρAV³) = 0.2(1.225 kg/m³)A(15 miles/h * 1069.34 m/mile * 1 hour/3600 s)³
P,actual₁ = 21.67A
P,actual₂ = 0.4(1/2 ρAV³) = 0.2(1.225 kg/m³)A(10 miles/h * 1069.34 m/mile * 1 hour/3600 s)³
P,actual₂ = 6.42 A

Therefore, ΔP,actual = 21.67A - 6.42A = 15.25A Watts